20y^2-3y-9=

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Solution for 20y^2-3y-9= equation:


Simplifying
20y2 + -3y + -9 = 0

Reorder the terms:
-9 + -3y + 20y2 = 0

Solving
-9 + -3y + 20y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-3 + -5y)(3 + -4y) = 0

Subproblem 1

Set the factor '(-3 + -5y)' equal to zero and attempt to solve: Simplifying -3 + -5y = 0 Solving -3 + -5y = 0 Move all terms containing y to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -5y = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -5y = 0 + 3 -5y = 0 + 3 Combine like terms: 0 + 3 = 3 -5y = 3 Divide each side by '-5'. y = -0.6 Simplifying y = -0.6

Subproblem 2

Set the factor '(3 + -4y)' equal to zero and attempt to solve: Simplifying 3 + -4y = 0 Solving 3 + -4y = 0 Move all terms containing y to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -4y = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -4y = 0 + -3 -4y = 0 + -3 Combine like terms: 0 + -3 = -3 -4y = -3 Divide each side by '-4'. y = 0.75 Simplifying y = 0.75

Solution

y = {-0.6, 0.75}

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